a cylindrical tube open at both ends is made of iron 3 cm thick if the external diameter is 42 cm and the length of the tube is 140 cm find the volume of the metal used in it
sanjayjha455:
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volume of a cylinder is given by pi(r)^2l
where r is the radius
and l is the length of the cylinder
according to your question r(external) = 50/2 = 25cm
and l = 140cm
therefore volume of cylinder is= 3.14x(25)^2x140
=274750cm^3
thickness of cylindrical tube is 2cm
therefore inner radius will be 25-2=23cm
therefore inner volume of the cylinder will be 3.14x(23)^2x140
=232548.4cm^3
the volume of iron it need=274750-232548.4=42201.6cm^3l
where r is the radius
and l is the length of the cylinder
according to your question r(external) = 50/2 = 25cm
and l = 140cm
therefore volume of cylinder is= 3.14x(25)^2x140
=274750cm^3
thickness of cylindrical tube is 2cm
therefore inner radius will be 25-2=23cm
therefore inner volume of the cylinder will be 3.14x(23)^2x140
=232548.4cm^3
the volume of iron it need=274750-232548.4=42201.6cm^3l
Answered by
14
Step-by-step explanation:
Answer given above is wrong
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