Question

Prove that (1-cos^2A)sec^2A=tan^2A

Answer 1

(1 - cos^2A ) sec^2A 

⇒ (sin^2A)(sec^2A)  [ 1- cos^2A = sin^2A]

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We know,   SinA = $\frac{height}{hypotenuse}$
                   SecA =$\frac{hypotenuse}{base}$

then,

sin^2 A × sec^2 A

⇒ $\frac{height^2}{hypotenuse^2}$×$\frac{hypotenuse^2}{base^2}$

⇒ $\frac{height^2}{base^2}$

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We know, height/base = tanA
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⇒ tan^2A 



hence,proved


i hope this will help you

(-:

Answer 2

don't report if u don't understand okay..
first tell me which step u not understand so that I can edit the answer...
and if u understand and this is correct so mark as brainlist plzz