A cylindrical tube open at both ends ,is made of metal . the internal diameter of the tube is 10.4cm and it's length is 25cm .the thickness of the metal is 8mm everywhere. Calculate the volume of the metal.
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Vol. of cylinder is πr^2h
inner vol. is π(5.2)^2*25
outer vol is π(5.2+0.8)^2*25
Net vol. of metal is =outer - inner
inner vol. is π(5.2)^2*25
outer vol is π(5.2+0.8)^2*25
Net vol. of metal is =outer - inner
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