A cylindrical tube opens at both end is made of metal.The internal diameter of the tube is 11.2cm and its length is 21cm. The metal thickness is 0.4cm. Calculate the volume of the metal.
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1
If cylinder has inner diameter is 10.4cm and thickness is 8mm=0.8cm
therefore outer diameter is 11.2cm
therefore volume with outer diameter is
=Πr^2h=3.14×11.2×11.2×25=9847.04cm^3
and volume with diameter inner 10.4cm is
=3.14×10.4×10.4×25=8490.56cm^3
Now volume of metal is
=9847.04-8490.56=1356.48cm^3
therefore outer diameter is 11.2cm
therefore volume with outer diameter is
=Πr^2h=3.14×11.2×11.2×25=9847.04cm^3
and volume with diameter inner 10.4cm is
=3.14×10.4×10.4×25=8490.56cm^3
Now volume of metal is
=9847.04-8490.56=1356.48cm^3
GODwin99:
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is this dp yours?
I think u took this dp from google....
Answered by
8
Solution :
Internal diameter = 11.2cm
Internal radius = 11.22
= 5.6m
Length of the tube = 21 cm
Volume of the internal cylinder = π r² h
=> 22×5.6×5.6×217
=> 2069.76 cm²
External radius = R = (5.6 + 0.4)
Volume of the external cylinder =πR²h
=> 22×6×6×217
=>2376cm²
Volume of the metal :
=> volume of external diameter - volume of internal diameter.
=> (2376 - 2069.76) cm²
=> 306. 24 cm²
Answer: 306. 2 cm² .
#thankyou!!
Internal diameter = 11.2cm
Internal radius = 11.22
= 5.6m
Length of the tube = 21 cm
Volume of the internal cylinder = π r² h
=> 22×5.6×5.6×217
=> 2069.76 cm²
External radius = R = (5.6 + 0.4)
Volume of the external cylinder =πR²h
=> 22×6×6×217
=>2376cm²
Volume of the metal :
=> volume of external diameter - volume of internal diameter.
=> (2376 - 2069.76) cm²
=> 306. 24 cm²
Answer: 306. 2 cm² .
#thankyou!!
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