Question

A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm
water weighs lg, find the depth of water.
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Answer 1

${\underline{\underline{\huge{\mathfrak{\green{Answer:-}}}}}}$

Hey Mate!!

1 gram = 1 cm³

⇒ 154 g = 154 cm³

Volume of Cylinder = πr²h

→ 154 = $\frac{22}{7}$ × 3.5 × 3.5 × h

→ 154 = 22 × 0.5 × 3.5 × h

→ 154 = 38.5 × h

→ h = 154 ÷ 38.5

→ ${\boxed{\boxed{\huge{\sf{\red{h=4\: cm}}}}}}$

Answer 2

Answer:

(height)depth of water=4cm

Step-by-step explanation:

volume of cylinder=πr^2h

r=3.5

h=?

volume=154

154=π(3.5)^2h

154/12.25π=h

on solving it

h=4cm