A/cylindrical vessel is filled with equal amounts of weight of mercury and water.The overall height of the two layers is 29.2cm specific gravity of mercury is 13.6 then the pressure of the liquid at the bottom of the vessel is
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- Question⇒ A/cylindrical vessel is filled with equal amounts of weight of mercury and water.The overall height of the two layers is 29.2cm specific gravity of mercury is 13.6 then the pressure of the liquid at the bottom of the vessel is
Explanation:
- # Given-
- Mw = Mhg
- Lw + Lhg = 29.2 cm
- ρhg/ρw = 13.6
- # Solution-
- We have
- Mw = Mhg
- ρw.A.Lw = ρhg.A.Lhg
- ρhg / ρw = Lw / Lhg
- 13.6 = Lw / Lhg
- Lw = 13.6 Lhg
- Also, Lw + Lhg = 29.2
- 13.6 Lhg + Lhg = 29.2
- Lhg (13.6+1) = 29.2
- Lhg = 29.2 / 14.6
- Lhg = 2 cm = 20 mm Hg
- As Mw = Mhg
- Pw = Phg
- P = Pw + Phg = 2 Phg
- P = 20×2 = 40 mm Hg Answer
- Therefore total pressure will be 20×2 = 40 mm Hg. Answer
- Hope this is useful...
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