A die is thrown once find the probability of getting multiple of 3
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Here is your answer:
When the dice is thrown the possibility of numbers to come are 1,2,3,4,5,6,
According to the question, we want only multiple of 3
So from 1 to 6 there are only 2 multiples of 3 that are 3 and 6
Now,
Probability =
No. of Favourable outcome /
Total no. of outcomes
Favorable outcome= 2 (3, 6)
Total outcomes = 6 (1, 2, 3, 4, 5, 6)
Therefore ,
Probability = 2 / 6
= 1 / 3
Answer :- 1/ 3
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