Ad is median of triangle abc.Prove that,ab2 + ac2=2(ad2+bd2)
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- Question⇒ Ad is median of triangle abc.Prove that,ab2 + ac2=2(ad2+bd2)?
Step-by-step explanation:
- In ABC, if AD is the median, then show that AB2 + AC2 = 2[AD2 + BD2].
- Given: AD is a median in ABC.
- To prove: AB2 + AC2 = 2[AD2 + BD2]
- Construction: Draw AE BC
- Proof:
- In right triangles AEB and AEC, using Pythagoras theorem
- AB2 + AC2 = BE2 + AE2 + EC2 + AE2 = 2AE2 + (BD - ED)2 + (ED + DC)2
- = 2AE2 + 2ED2 + BD2 + DC2
- AB2 + AC2 = 2AE2 + 2ED2 + 2BD2 [since BD = DC]
- = 2 (AE2 + ED2 + BD2)
- = 2 (AD2 + BD2)
- [Using Pythagoras theorem in AED]
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