a cylindrical vessel of diameter 10 cm and height 8 cm is filled with water up to the rim.When 120 spherical lead shots are dropped into it,one-tenth of the water flows out.Find the radius of each lead shot?
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Heya,
Solution to your question is:-
Volume of cylinder = pi r² h ( r radius, h height)
=> volm = pi 5² *8 = 200 pi cu cm
1/10 of (200 pi) flows out
=> 20 pi cu cm water flows out
=> 20 pi = volume of 120 spherical lead shots ( by Archimedes’ principle , volume of displaced water = volume of objects immersed)
Hence, volume of 1 spherical shot = (20pi/120)cu cm = (pi/6) cu cm
:> 4/3 pi r^3 = pi /6 ( r is radius of the lead shot)
=> r^3 = 3/(6*4)
= r^3 = 1/(2*2*2)
=> r = 1/2 = 0.5 cm
【RADIUS = 0.5 cm】
HOPE THIS HELPS YOU:-))
@Ashu
Solution to your question is:-
Volume of cylinder = pi r² h ( r radius, h height)
=> volm = pi 5² *8 = 200 pi cu cm
1/10 of (200 pi) flows out
=> 20 pi cu cm water flows out
=> 20 pi = volume of 120 spherical lead shots ( by Archimedes’ principle , volume of displaced water = volume of objects immersed)
Hence, volume of 1 spherical shot = (20pi/120)cu cm = (pi/6) cu cm
:> 4/3 pi r^3 = pi /6 ( r is radius of the lead shot)
=> r^3 = 3/(6*4)
= r^3 = 1/(2*2*2)
=> r = 1/2 = 0.5 cm
【RADIUS = 0.5 cm】
HOPE THIS HELPS YOU:-))
@Ashu
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