calculate normality of 21% (w/v)H2SO4 solution.
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21% w/v H2SO4 means 21 g of H2SO4 is present in 100 ml of solution.
No. of equivalents of H2SO4 = weight / Gram equivalent of H2SO4
= (21 / 49) moles
Normality = (Equivalents × 1000) / Volume of solution
= [(21 / 49) × 1000] / 100
= 4.28 N
No. of equivalents of H2SO4 = weight / Gram equivalent of H2SO4
= (21 / 49) moles
Normality = (Equivalents × 1000) / Volume of solution
= [(21 / 49) × 1000] / 100
= 4.28 N
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