a cylindrical vessel of diameter 14 metre and height 42 centimetre is fixed symmetrically in side a similar vessel of diameter 16 cm and height 42cm the total space between the two vessels is filled with cork dust for heat insulation for proposes how many cubic centimetres of cork dust will be required
Answers
Given height of cylindrical vessel (h) = 42cm Inner radius of a vessel (r1) = 14/2 cm =7 cm Inner radius of a vessel (r2) = 16/2 cm = 8cm
Thank you it took long to type so plz mark as brainliest.
Answer:
64671552 cubic cm
Step-by-step explanation:
radius of outter cylinder =r=14/2=7 m = 700 cm
radius of inner cylinder =R=16/2=8 cm
height of inner cylinder =height of outter cylinder=h=42 cm
volume of cork dust requird= volume of outter cylinder-volume of inner cylinder
= π*R*R*h - π*r*r*h
= πh(R+r)(R-r)
= 22/7*42*(700+8)(700-8)
= 64671552 cubic cm
Therefore, cork dust required for heat insulation for proposes is 64671552 cubic cm.
Think it helps