Math, asked by ankita12683, 10 months ago

a cylindrical vessel of diameter 14 metre and height 42 centimetre is fixed symmetrically in side a similar vessel of diameter 16 cm and height 42cm the total space between the two vessels is filled with cork dust for heat insulation for proposes how many cubic centimetres of cork dust will be required​

Answers

Answered by AdityaYadav000
0

Given height of cylindrical vessel (h) = 42cm Inner radius of a vessel (r1) = 14/2 cm =7 cm Inner radius of a vessel (r2) = 16/2 cm = 8cm

Thank you it took long to type so plz mark as brainliest.

Answered by madhvsingh06
0

Answer:

64671552‬ cubic cm

Step-by-step explanation:

radius of outter cylinder =r=14/2=7 m = 700 cm

radius of inner cylinder =R=16/2=8 cm

height of inner cylinder =height of outter cylinder=h=42 cm

volume of cork dust requird= volume of outter cylinder-volume of inner cylinder

                                    = π*R*R*h - π*r*r*h

                                    = πh(R+r)(R-r)

                                    = 22/7*42*(700+8)(700-8)

                                    = 64671552‬ cubic cm

Therefore, cork dust required for heat insulation for proposes is 64671552 cubic cm.

                                       Think it helps

Similar questions