Question

A cylindrical vessel of diameter 14cm and height 42cm is fixed symmetrically inside a similar vessel of diameter 16cm and height 42cm. The total space between two vessels is filled with cork dust for heat insulation purpose. How many cubic cms of cork dust will be required? it's Urgent

Answer 1

Answer:

Step-by-step explanation:

Given height of cylindrical vessel (h) = 42cm

Inner radius of a vessel (r1) = 14/2 cm =7 cm

Inner radius of a vessel (r2) = 16/2 cm = 8cm

Vol. Of cylinder ( r2² - r2¹) h

Pie (8²- 7²) 42

Pie(64-49)42

15×42×pie

630pie

=1980cm³

Volume of vessel = 1980cm²

Answer 2

Answer:

1980 cm³

Step-by-step explanation:

⇒ Given, External diameter = 16 cm.

Then, radius R = 16/2 = 8 cm.

⇒ Given, Internal diameter = 14 cm.

Internal radius r = 14/2 = 7 cm.

⇒ Height of vessel = 42 cm.

∴ Volume of cork dust = Volume of external cylinder - Internal cylinder

                                      = πR²h - πr²h

                                      = πh(R² - r²)

                                      = (22/7) * 42 * (8² - 7²)

                                      = 22 * 6 * 15

                                      = 1980 cm³

Therefore, 1980 cm³ of cork dust will be required.

Hope it helps!