Question

In a class, there are 18 girls and 16 boys. The class teacher wants to choose one pupil for class monitor. What she does, she writes the name of each pupil on a card and puts them into a basket and mixes thoroughly. A child is asked to pick one card from the basket. What is the probability that the name written on the card is:
(i)the name of a girl
(ii)the name of a boy?

Answer 1

SOLUTION :  

Given : Number of girls in a class =  18 and Number of boys in a class =16  

Total number of students in the class 18 + 16 = 34

Total number of outcomes = 34

(i) Let E1 = Event  of getting the name of a girl

Number of girls in a class =  18

Number of outcome favourable to E1 = 18

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 18/34 = 9/17

Hence, the required probability of getting the name of a girl , P(E1) = 9/17.

(ii) Let E2 = Event  of getting the name of a boy

Number of boys in a class =  16

Number of outcome favourable to E2 = 16

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = 16/34 = 8/17

Hence, the required probability of getting the name of a boy , P(E2) = 8/17.

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

hey mate here is your answer ✌♥✌

let s be the sample space

so,n(s)=18+16

=34

now let E1 be the event that the picked card have a name of boy

so n(E1)=16

now

p(E1)=n(E1)/n(s)

=16/34

=8/17

now let E2 be the event that the picked card have a name of girl

so n(E2)=18

now

p(E2)=n(E2)/n(s)

=18/34

=9/17

hope it will help you

mark me brainliest ✌✌✌✌