Question

A cylindrical vessel, whose diameter and height both are equal to 30 cm is placed on a horizontal surface and a small particle p is placed in it at the distance of

Answer 1

The refractive index of water is n = 4/3.
= 30 − ℎ
= 20 − = 20 − (30 − ℎ) = ℎ − 10
using Snell’s law, we get sin = sin
sin =(ℎ − 10)/√ℎ2 + (ℎ − 10)^2

from the above

sin 45° =4/3[(ℎ − 10)/√ℎ2 + (ℎ − 10)^2]
9/2(ℎ^2 + (ℎ − 10)^2) = 16(ℎ − 10)^2
9 ℎ^2 = 23(ℎ − 10)^2

ℎ =√23 ∙ 10/√23 -3 =26.7 cm