A cylindrical vessel with open lid has a height of 1.4m and its base radius is 70cm this vessel has to be coated with zinc from both side then find the cost of coating if rate of coating is $3.5 per 1000 sq. cm...
No spam....
Glad if Siddhart sir... Solve it.....
Answers
A cylindrical vessel has an open lid .
This means that one of its circular surface is missing .
Surface area of the cylinder
The zinc has to be coated on the surface of the vessel.
We have to calculate the surface area of the cylinder:
Given :
radius ( r ) = 70 cm
height ( h ) = 1.4 m = 140 cm
Surface area with one lid open = 2 π r h + π r²
==> 2 π ( 70 cm ) × ( 140 cm ) + π ( 70 cm )²
==> 2 × 22/7 × 70 cm × 140 cm + 22/7 × 4900 cm²
==> 44 × 10 cm × 140 cm + 22 × 700 cm
==> 61600 cm² + 15400 cm²
==> 77000 cm²
Costing
Coating has to be done $ 3.5 per every 1000 cm²
For 1 cm² , cost = $ 3.5 / 1000
For , 77000 cm² cost = $ 3.5 / 1000 × 77000
= $ 3.5 × 77
= $ 269.5
The cost of coating is $ 269.5
Hope it helps :)
Plz comment if you have doubts
__________________________________________________________________
Answer:
269.5
Step-by-step explanation:
Given, Radius of vessel = 70 cm.
Given, height of vessel = 1.4m = 140 cm.
Total surface area of the vessel = 2πrh + πr²
= 2 * (22/7) * (70) * (140) + (22/7) * (70)²
= 61600 + 15400
= 77000 cm²
Rate of tin-coating = 3.5 per 1000 cm².
∴ Total cost = (77000 * 3.5)/1000
= 269500/1000
= 269.5
Hope it helps!