Question

A cylindrical water tank of diameter 1.4m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at the rate of 2 m per secondcalculatethe time it takes to fill the tank

Answer 1

Step-by-step explanation:

Given  

A cylindrical water tank of diameter 1.4 m and height 2.1 m is being fed by a pipe of diameter 3.5 cm through which water flows at the rate of 2 m   per second calculate the time it takes to fill the tank

• Given diameter = 1.4 m
• Radius = 1.4 / 2 = 0.7 m  
• Also h = 2.1 m
• We know that volume of tank = π r^2 h
•                                                = 22/7 x 0.7 x 0.7 x 2.1
• Now dimensions of pipe will be
• Diameter = 3.5 cm
• Radius = D / 2
•            = 3.5 / 2
•            = 3.5 / 200 m
• Height = 2 m
• Now volume of water delivered in 1 sec will be π r^2 h
•                                                                          = 22/7 x 3.5 / 200 x 3.5/200 x 2 m^3
• When tank is filled let time be x.
• Volume of tank = volume of water delivered in x sec
• So 22/7 x 0.7 x 0.7 x 2.1 = 22/7 x 3.5 / 200 x 3.5/200 x 2 x x m^3
• So x = 0.7 x 0.7 x 2.1 x 200 x 200 / 3.5 x 3.5 x 2
•         = 1680 sec
•        = 1680 / 60
•         = 28 min
• So the tank will be fully filled in 28 min.

Answer 2

Given diameter = 1.4 m

Radius = 1.4 / 2 = 0.7 m

Also h = 2.1 m

We know that volume of tank = π r^2 h

= 22/7 x 0.7 x 0.7 x2.1

Now dimensions of pipe will be

Diameter = 3.5 cm

Radius = D / 2

= 3.5 / 2

= 3.5 / 200 m

Height = 2 m

Now volume of water delivered in 1 sec will be π r^2 h = 22/7 x 3.5 / 200 x 3.5/200 x 2 m^3

When tank is filled let time be x.

Volume of tank = volume of water delivered in x sec

So 22/7 x 0.7 x 0.7 x 2.1 = 22/7 x 3.5 / 200 x 3.5/200 x 2 x x m^3

So x = 0.7 x 0.7 x 2.1 x 200 x 200 / 3.5 x 3.5 x 2

= 1680 sec

= 1680 / 60

= 28 min

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