a cylindrical well is 21m deep.its outer and inner diameters are 21m and 14m respectively .find the cost of rennovating the inner curved surface and outer curved surface at rate of Rs25per square meter.
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height of the well (h) = 21m
outer diameter of the well = 21m
inner diameter of the well = 14m
Outer CSA of the well = 2×pi×r×h
= 2×(22/7)×(21/2)×21
= (44/7)(441/2)
= (44×441)/14
= 1386 m^2
cost for renovating outer CSA of the well
= 1386 × 25
= Rs 34650
Again,
Inner CSA of the well = 2×pi×r×h
= 2×(22/7)×(14/2)×21
= (44/7)×7×21
= (44/7)×21
= 44 × 21
= 924 m^2
cost for renovating inner CSA of the well
= 924 × 25
= Rs 23100
outer diameter of the well = 21m
inner diameter of the well = 14m
Outer CSA of the well = 2×pi×r×h
= 2×(22/7)×(21/2)×21
= (44/7)(441/2)
= (44×441)/14
= 1386 m^2
cost for renovating outer CSA of the well
= 1386 × 25
= Rs 34650
Again,
Inner CSA of the well = 2×pi×r×h
= 2×(22/7)×(14/2)×21
= (44/7)×7×21
= (44/7)×21
= 44 × 21
= 924 m^2
cost for renovating inner CSA of the well
= 924 × 25
= Rs 23100
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