A cylindrical well is 21m deep .its outer and inner diameters are 21m and 14 m respectively.find the cost of renovating the inner curved surface and outer curved surface at the rate of rupees25per meter square.
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CSA of inner side + CSA of outer side
2πrh+ 2πRh
2πh(r+R)
2×22/7×21(7+10.5)
528m^2
cost of renovating 1m^2 area = Rs.25
cost of renovating 528m^2 area = Rs.25×528
Rs.13,200
2πrh+ 2πRh
2πh(r+R)
2×22/7×21(7+10.5)
528m^2
cost of renovating 1m^2 area = Rs.25
cost of renovating 528m^2 area = Rs.25×528
Rs.13,200
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