Math, asked by pritty78, 1 year ago

a cylindrical well is of height 3.5 feet above the ground the level of water is 7feet below the ground level. if the volume of waer in the well is half the volume of the capacity of the well find the total height of the well


manglani66: what is the answer for this question..? Can u please tell me.
pritty78: 21 feet

Answers

Answered by CarlynBronk
78

Answer with explanation:

Height of well above the ground level = 3.5 feet

Level of water , which is below the ground level in the well = 7 feet

Let , the height of water in the well from the base of the well = H

So, total height of well = 3.5 +7+H= (10.5 + H) Feet

Let Radius of well = R feet

It is given that volume of water in the well is half of volume of capacity of well.

Since ,well is in the form of cylinder.

Volume of cylinder=πr²h

→2 ×π×R²×H= π×R²×(10.5+H)

→ 2 H= H +10.5

→2 H - H= 10.5

H=10.5

So, total height of well = 10.5 + 10.5=21 feet

Answered by collector25
3

Answer:

Answer of this question is 21 feet

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