Question

A
D
2) ABCD is a rectangle AB = 7cm.,
BC = 24 cm., OB = 12.5 cm.
ZABD = 35° find DC , AD, BD, AC
ZBDC and ZDBC
C С
B​

Answer 1

Answer:

BY APPLYING PYTHAGORAS THEROM ANSWER IS 25

Answer 2

Given : ABCD is a rectangle AB = 7cm. BC = 24 cm., OB = 12.5 cm.

∠ABD = 35°

To  find :  DC , AD, BD, AC

∠BDC and ∠DBC  

Solution:

ABCD is a rectangle

Hence opposite sides are equal

DC = AB =   7  cm

AD = BC = 24 cm

Diagonal are equal and  bisects each others

BD = 2 (OB) = 2 (12.5) = 25 cm

AC = BD = 25 cm

It can be verified using Pythagoras

7² + 24² = 25²

opposite side of rectangle are parallels

=> ∠BDC  = ∠ABD   ( alternate angles)

∠ABD = 35°

=> ∠BDC  =  35°

all angle of rectangle are 90°

∠DBC   + ∠ABD = 90°

=> ∠DBC   + 35° = 90°

=> ∠DBC  =  55°

NOTE : However ∠ABD  must be 73.74°  which is given   35° but we used whats given in question

Learn More:

13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 cm ...

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CICSE)13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 ...

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