A dam has height H and a width b. Assuming that the water level reaches at the top, find the average force exerted on the dam for H - 60 m and b - 200 m.
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Answer:
force of buoyancy = density of liquid * acceleration due to gravity * volume of object (assuming that the dam is triangular in shape with width 'h')
= 10^3 * 10 * 1/2*200*60*60
= 3.6*10^19
Answered by
3
force of buoyancy = density of liquid * acceleration due to gravity * volume of object (assuming that the dam is triangular in shape with width 'h')
= 10^3 * 10 * 1/2*200*60*60
= 3.6*10^19
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