Physics, asked by igorcolmenares, 9 months ago

A DC/DC buck converter converts 42V to 14V. The input current is 10A. If the switching is 50kHz what will the period be?

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Answered by Anonymous
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Power = Voltage × Current

Power input :

42 × 10 = 420 watt

Efficiency = (power output / power input) × 100%

100 = (P / 420) × 100

1 = P / 420

P = 420 watts

Out put current :

Current = 420 / 14 = 30A

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Answer:

Explanation:

Power = Voltage × Current

Power input :

42 × 10 = 420 watt

Efficiency = (power output / power input) × 100%

100 = (P / 420) × 100

1 = P / 420

P = 420 watts

Out put current :

Current = 420 / 14 = 30A

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