A dealer buys 30 wireless sets, all at the same price. He sells 20 of them at a profit of 16 percent and has to sell the remaining 10 at a loss of 4% What is the percentage profit on the deal?
Answers
GIVEN :-
- A dealer buys 30 wireless sets all at same price.
- He sells 20 of them at a profit of 16% and 10 of them at loss of 4%.
TO FIND :-
- Net profit on the deal.
SOLUTION :-
Let price of each wireless set be 'x'.
So , price of 30 sets will be 30x.
♦ He sells 20 of them at 16% profit.
Buying price of 20 sets = 20x
→ Selling price(20 sets) =20x + 16% of 20x
→ Selling price(20 sets)=20x + (16/100)20x
→ Selling price(20 sets) =20x + (320x/100)
→ Selling price(20 sets) =20x + (32x/10)
→ Selling price (20 sets) = 232x/10
♦ He sells 10 of them at 4% loss.
Buying price of 10 sets = 10x
→ Selling price (10 sets) = 10x - 4% of 10x
→ Selling price (10 sets) = 10x - (4/100)10x
→ Selling price (10 sets) = 10x - (4x/10)
→ Selling price (10 sets) = 96x/10
★ Total selling price = (232x/10) + (96x/10)
Total selling price = 328x/10
Total selling price = 32.8x
___________________
% Profit =
→ [(selling price - buying price)/buying price] × 100
→ [(32.8x - 30x)/30x] × 100
→ [2.8x/30x] × 100
→ 0.09 × 100
→ 9%
Hence , there is total 9% of profit.