Question

A dealer gets Rs 470 more if instead of selling a table at a loss of 10% , it is sold at a gain of 10%. Find the cost price of the table.

Answer 1

Solution:-
Let us assume that the cost price of the table be 'x' Rs.
Then in the case of loss = x - (10 % of x)
⇒ x - 10x/100
⇒ x - x/10
⇒ 9x/10 Rs.
⇒ now in case of profit,
⇒ x + (10 % of x)
⇒ x + 10x/100
⇒ x + x/10
⇒ 11x/10 Rs.
The difference between profit and loss = (11x/10) - (9x/10) = 470
⇒ 2x/10 = 470
⇒ 2x = 4700
⇒ x = 4700/2
⇒ x = 2350
So, cost price of table is 2350 Rs.

Answer 2

Step-by-step explanation:

Solution:-

Let the CP of table→ x

Then in case of loss→ x-(10% of x)

In case of loss→ x-10/100×x

→x-x/10

→9x/10

In case of profit:-

X+(10%+x)

x+ (10/100×x)

x+x/10

11x/10

A/q

→11x/10-9x/10 =470

→2x/10= 470

→x= 470×10/2

→x=2350