Math, asked by sakshisingh7015, 11 months ago

A dealer gives as much discount as the markup above the cost price

Answers

Answered by amitnrw
1

Answer:

X²/100

Step-by-step explanation:

A dealer gives as much discount as the markup above the cost price

Let say Cost Price = C

Markup above Cost Price = X %

Then Markup Price = C + (X/100)C  = C(1 + X/100)

Discount on Markup price = X%

Discount = (X/100)C(1 + X/100)

Selling Price = C(1 + X/100) -  (X/100)C(1 + X/100)

= C(1 + X/100)(1 - X/100)

= C( 1  - (X/100)²)

Loss = C - C( 1  - (X/100)²)  =  C(X/100)²

Loss % =  (C(X/100)²/C) * 100

= X²/100

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