Ifthe number X+3,2X+1and X-7 are in A.P .findthe value of X
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Answer:
a1 = x+3
a2 = 2x+1
a3 = x-7
d1 (common difference 1) = a2 - a1
= 2x+1 - (x+3)
d2 (common difference 2) = a3 - a2
= x-7 - (2x+1)
given : numbers x+3 , 2x+1 and x-7 are in A.P
so d1 = d2
2x+1 - x-3 = x-7 - 2x-1
x-2 = -x-8
2x = -6
x = -3
Explanation:
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