Question

A dealer mixes tea costing RS 6.92 per kg. with tea costing RS 7.77 per kg. and sells the mixture at RS 8.80 per kg. and earns a profit of 17.5% on his sale price. in what proportion does he mix them?​

Answer 1

Required ratio = 3 : 2

Step-by-step explanation:

Let x kg of the 1st type of tea is mixed with y kg of the 2nd type of tea.

Then the cost price of the mixed tea is

= Rs. (6.92x + 7.77y)/(x + y) per kg

Given that, the selling price of the mixed tea is Rs. 8.80 per kg

So profit = selling price - cost price

= Rs. 8.80 - (6.92x + 7.77y)/(x + y)

= Rs. (8.80x + 8.80y - 6.92x - 7.77y)/(x + y)

= Rs. (1.88x + 1.03y)/(x + y)

By the given condition,

profit = selling price * 17.5%

i.e., (1.88x + 1.03y)/(x + y) = 8.80 * 17.5/100

or, (1.88x + 1.03y)/(x + y) = 1.54

or, 1.88x + 1.03y = 1.54x + 1.54y

or, 1.88x - 1.54x = 1.54y - 1.03y

or, 0.34x = 0.51y

or, x/y = 0.51/0.34

or, x/y = 3/2

i.e., x : y = 3 : 2

∴ the required ratio is 3 : 2

Answer 2

Answer:

3:2.......................