Question

a dealer paid rupees 3750 for two headphones. He sold one at the profit of 20% and other at the loss of 20% . If the selling price of both the sets were same, find the cost price of each headphone​

Answer 1

$\bold{ANSWER≈}$

• Let 1st radio price will be X And 2nd radio price is Y. So both radio price is 6000rs

Writting sentence 1) into equation we get

X+Y=6000……..………………..(1)

• 1st radio sold at 20% profit & 2nd radio sold at 10% loss. And shopkeeper gained 2% profit on 6000rs investment

By writing sentence 2) into equation we get

1.2X+0.9Y=6120(102% 6000)………. (2)

By solving 1 & 2

We get

X=2400

Y=3600

Answer 2

Answer:

Let SP - x

2 headphone 3750-x

20x/100

1x/5

loss 20/100

1/5

1x/5 = 1/5(3750-x)

1x = 3750-x

2x=3750

x= 1875

sp 3750-x

3750-1875

=1875

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