A dealer sells an article for Rs. 75 and gains as much per cent as the cost price of the article. Find the cost price of the article.
Please explain clearly with proper solution...
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Answers
hey mate...
here is your answer...
SP=75 Rs.
Let the profit% is x%.
So the cost price is x Rs.
Profit= SP- CP
= 75-x Rs.
Profit%= (profit/CP)×100
x= (75-x)/x ×100
x^2= (75-x)×100
x^2 = 7500-100x.
x^2+100x-7500=0.
x^2 + 150x-50x-7500=0.
x(x+150)-50(x+150)=0.
(x-50)(x+150)=0.
Root 1
x-50=0
x=50
Root 2
x+150=0
x=-150 coz the value of x cannot be 0 we'll discard this value
Hence the cost price is 50Rs
And profit% is 50%.
Hope it helps...
Answer:
Step-by-step explanation:
SP=75 Rs.
Let the profit% is x%.
So the cost price is x Rs.
Profit= SP- CP
= 75-x Rs.
Profit%= (profit/CP)×100
x= (75-x)/x ×100
x^2= (75-x)×100
x^2 = 7500-100x.
x^2+100x-7500=0.
x^2 + 150x-50x-7500=0.
x(x+150)-50(x+150)=0.
(x-50)(x+150)=0.
case 1
x-50=0
x=50
case 2
x+150=0
x=-150 which is not possible
thus the cost price is rs50
thus profit% is 50%.