A dealer sells an article for Rs.75 and gains as much per cent as the cost priced of the article. Find the cost price of the article.
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4
SP=75 Rs.
Let the profit% is x%.
So the cost price is x Rs.
Profit= SP- CP
= 75-x Rs.
Profit%= (profit/CP)×100
x= (75-x)/x ×100
x^2= (75-x)×100
x^2 = 7500-100x.
x^2+100x-7500=0.
x^2 + 150x-50x-7500=0.
x(x+150)-50(x+150)=0.
(x-50)(x+150)=0.
Root 1
x-50=0
x=50
Root 2
x+150=0
x=-150 coz the value of x cannot be 0 we'll discard this value.
Hence the cost price is 50Rs
And profit% is 50%.
Hope it
Let the profit% is x%.
So the cost price is x Rs.
Profit= SP- CP
= 75-x Rs.
Profit%= (profit/CP)×100
x= (75-x)/x ×100
x^2= (75-x)×100
x^2 = 7500-100x.
x^2+100x-7500=0.
x^2 + 150x-50x-7500=0.
x(x+150)-50(x+150)=0.
(x-50)(x+150)=0.
Root 1
x-50=0
x=50
Root 2
x+150=0
x=-150 coz the value of x cannot be 0 we'll discard this value.
Hence the cost price is 50Rs
And profit% is 50%.
Hope it
Answered by
6
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