Question

A dealer sold a camera for ₹1080 gaining 1/8 of its cost price. Find (1) the cost price of the camera and (2) the gain per cent earned by the dealer

Answer 1

$\textbf{Answer}$

Suppose cost price is CP Rs.
&
Selling price = SP Rs.

$\textbf{Since Selling Price is 1080 Rs.,}$

SP = 1080 Rs.
Dealer gained 1/8 of cost price.

=> $\textbf{SP = CP + Gain on CP}$

=> SP = CP + (1/8)CP

=> CP + CP/8 = 1080

=> (9CP)/8 = 1080

=> CP = (1080×8)/9

=> CP = 120 × 8

=> CP = 960 Rs.

$\textbf{Total gain = SP - CP}$
=> Total gain = 1080 - 960
=> $\textbf{Total gain = 120 Rs}$

$\textbf{Gain Percent=(Total gain/CP)(100) }$ %

=> Gain percent = (120/960) × 100
=> Gain percent = 100/8
=> Gain percent = 12.5 %

$\textbf{Cost Price = Rs 960}$
$\textbf{Gain Percentage = 12.5}$%

$\textbf{Hope My Answer Helped}$
$\textbf{Answer}$

Answer 2

Answer :

Let us consider that the cost price of the camera = Rs x

By the given condition,

x + x/8 = 1080

or, (8x + x)/8 = 1080

or, 9x = 8 × 1080

or, x = (8 × 1080)/9

or, x = 960

Therefore, the cost price of the camera is Rs 960

Gain = Rs 960/8 = Rs 120

Therefore, gain percent

= 120/960 × 100 %

= 12.5 %

Hope it helps! (: