Question

a dealer sold a camera for ₹1080 of its cost price. Find (1) the cost price of the camera, and (2) the gain per cent earned by the dealer ​

Answer 1

Answer:

Suppose cost price is CP Rs.

&

Selling price = SP Rs.

SP = 1080 Rs.

Dealer gained 1/8 of cost price.

=>

=> SP = CP + (1/8)CP

=> CP + CP/8 = 1080

=> (9CP)/8 = 1080

=> CP = (1080×8)/9

=> CP = 120 × 8

=> CP = 960 Rs.

=> Total gain = 1080 - 960

=>

%

=> Gain percent = (120/960) × 100

=> Gain percent = 100/8

=> Gain percent = 12.5 %

Answer 2

Explanation:

1) cp=(sp*100)

=1080*100

=108000

2) cp/sp*100

=108000/1080*100

profit is of 10000rs

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