A dealer sold a camera for Rs.1080 gaining 1/8of it's cost price.find cost price of the camera and the gain percent earned by the dealer.
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Answered by
276
cost price =x
Selling price =1080
profit=x/8
selling price=x+x/8=9x/8
1080=9x/8
1080=9x/8
x=960
Selling price =1080
profit=x/8
selling price=x+x/8=9x/8
1080=9x/8
1080=9x/8
x=960
Answered by
126
A dealer sold a camera for Rs.1080
gaining 1/8of its cost price then the cost price of the camera as well as the gain percent earned by the dealer will be in general
the Selling price=1080,
let cost price=C
therefore gain=1/8C and the Selling price=C+1/8C=1080
by solving C we have:9/8C=1080
then C=960
and gain =1/8*960=120
and the percentage gain=120/960*100%=12.5%
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