A dealer sold acamera for rs 1080 gaining 1/8 of its cost price.find (i) the cost price of the camera,and (ii) the gain per cent earned by the dealer.
Answers
Answered by
0
ANSWER
Cost of camera dealer sold= Rs.1080
cost price of camera =Rs.x
A/c the question
x+
8
1
x=1080
⇒x=(
8
9
)=1080
x=
9
(1080)8
=(120)8=960
cost price of
camera =Rs.960
% gain =
960
1080−960
×100=12.5%
Answered by
5
Your Answer ⬇
cost price = x
selling price = 1080
profit = x/8
selling price = x + x/8 = 9x/8
1080 = 9x/8
x = 960
Hope this will help you ..
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