Question

a)Define horizontal range and derive formula for it in case of oblique projection.
b)when is range is maximum and derive formula for maximum height.


Plz answer this....

Answer 1

Maximum Height


The maximum height, ymax
vy 2 = voy2 + 2 ay (y - yo)

yo = 0, and, when the projectile is at the maximum height, vy = 0.

Solving the equation for ymax gives:

ymax = - voy2 /(2 ay)

Plugging in voy = vo sin(q) and ay = -g, gives:

ymax = vo2sin2(q) /(2 g)