a)Define horizontal range and derive formula for it in case of oblique projection.
b)when is range is maximum and derive formula for maximum height.
Plz answer this....
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Maximum Height

The maximum height, ymax
vy 2 = voy2 + 2 ay (y - yo)
yo = 0, and, when the projectile is at the maximum height, vy = 0.
Solving the equation for ymax gives:
ymax = - voy2 /(2 ay)
Plugging in voy = vo sin(q) and ay = -g, gives:
ymax = vo2sin2(q) /(2 g)

The maximum height, ymax
vy 2 = voy2 + 2 ay (y - yo)
yo = 0, and, when the projectile is at the maximum height, vy = 0.
Solving the equation for ymax gives:
ymax = - voy2 /(2 ay)
Plugging in voy = vo sin(q) and ay = -g, gives:
ymax = vo2sin2(q) /(2 g)
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