A deposit of fine sand has a void ratio of 0.54 and the specific gravity of solid particle is 2.65. Compute the safe exit gradient with a factor of safety of 4.
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Explanation:
dont know sorrrrry. please sorry
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Answer:
icr= G-1/1+e , 2.65-1/1+0.54 = 1.07
FOS= icr/isafe , isafe=1.07/4
=0.27
Explanation:
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