a)derive the formula for maximum height attained by a projectile
b) what is a horizontal range of projectile derive its formula
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vx=ucosθvy2−uy2=2ayvy=0(atmaxheightH)uy=usinθay=−gHPuttingthesevalues,0=(usinθ)2−2gHH=2gu2sin2θ
hope you are satisfied with this
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