a design on the wall of room consist of 1000 tiles of the shape of parallelogram. if altitude and base of each tile is 10cm and 4cm respectively, find the cost of polishing the design at rate of rs 9.50dm square
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10cm = 1dm.
Given that Base of the tile = 4cm = 0.4dm.
We know that Area = l * b
= 1 * 0.4
= 0.4dm^2.
Given that total number of tiles in the room = 1000.
Therefore the total area of the floor = 1000 * 0.4 =400
Given that cost of polishing per dm^2 = 9.50dm.
Therefore the cost of polishing = 400 * 9.50
= 3800 rupees.
hope it helps you
Given that Base of the tile = 4cm = 0.4dm.
We know that Area = l * b
= 1 * 0.4
= 0.4dm^2.
Given that total number of tiles in the room = 1000.
Therefore the total area of the floor = 1000 * 0.4 =400
Given that cost of polishing per dm^2 = 9.50dm.
Therefore the cost of polishing = 400 * 9.50
= 3800 rupees.
hope it helps you
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