A design on the wall of room consists of 1000 tiles of the shape of parallelogram . If altitude and base of each tile is 10 cm and 4 cm , respectively find the cost of polishing the design at the rate of ₹ 9.50 square dm.
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Given that length of the tile = 10cm = 1dm.
Given that Base of the tile = 4cm = 0.4dm.
We know that Area = l * b
= 1 * 0.4
= 0.4dm^2.
Given that total number of tiles in the room = 1000.
Therefore the total area of the floor = 1000 * 0.4
= 400
Given that cost of polishing per dm^2 = 9.50dm.
Therefore the cost of polishing = 400 * 9.50
= 3800 rupees.
Hope this helps!
Given that Base of the tile = 4cm = 0.4dm.
We know that Area = l * b
= 1 * 0.4
= 0.4dm^2.
Given that total number of tiles in the room = 1000.
Therefore the total area of the floor = 1000 * 0.4
= 400
Given that cost of polishing per dm^2 = 9.50dm.
Therefore the cost of polishing = 400 * 9.50
= 3800 rupees.
Hope this helps!
rakesh112:
i think v. good
answer is wrong
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