Question

A design on the wall of room consists of 1000 tiles of the shape of the parallelogram. If altitude and base of each style is 10 centimetre and 4 centimetre respectively find the cost of polishing the design at the rate of rs. 9.50 per dm²

Answer 1

Area of parallelogram =base *height =10*4=40cmsq
1 design =40cmsq
So 1000 design =40000cmsq
Policing cost @9.50=40000*9.5=380000/
I think it is right answer If you like please mark as brainliest

Answer 2

Area of parallelogram = Base × Height

Base = 10cm
Height = 4cm

Therefore Area = 10 × 4 =
$40 {cm}^{2}$
No.of tiles = 1000
Therefore Area of the 1000 tiles =
$40000 {cm}^{2}$
Therefore the Cost of polishing the design at the rate of 9.50₹ per dm^2=

40,000 × 0.01 dm^2 × 9.50 = 3,800₹

Hope this helps!