Question

A design on the wall of room consists of 1000 tiles of the shape of parallelogram. It
altitude and base of each tile is 10 cm and 4 cm respectively, find the cost of polishing
the design at the rate of 9.50 per dm
​

Answer 1

Answer:

Given that length of the tile = 10cm = 1dm

Given that Base of the tile = 4cm = 0.4dm.

We know that Area = l * b

= 1 * 0.4

= 0.4dm^2.

Given that total number of tiles in the room = 1000.

Therefore the total area of the floor = 1000 * 0.4

= 400

Given that cost of polishing per dm^2 = 9.50dm.

Therefore the cost of polishing = 400 * 9.50

= 3800 rupees.