A design on the wall of room consists of 1000 tiles of the shape of parallelogram. If altitude and the base of each tile is 10 cm and 4 cm respectively, find the cost of polishing the design at the rate of rupees 9.50 per dm^2
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area of IIgm = base × height
are of IIgm = 10×4
= 40cm^2
1 dm = 10cm
cost of polishing 10cm=9.50rupees
cost of polishing 40cm= 9.50×40
: = 380 rupees
HOPE IT HELPS
are of IIgm = 10×4
= 40cm^2
1 dm = 10cm
cost of polishing 10cm=9.50rupees
cost of polishing 40cm= 9.50×40
: = 380 rupees
HOPE IT HELPS
yash2090:
1 dm^2 = 100cm^2 . So the ans is 3800 rs
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