A designer had to change the size of a regtangular carpet. He increased the lenght by 50% and decreased the width by 20%. By what percent was the area of the final item charged
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let length be l .
let breadth be b.
area = lb
Increased length = l + l ×50/100
= 3l/2
Decreased breadth = b - b ×20/100
= 4b/5
New Area = 3l/2 × 4n/5 = 6lb/5
Change in area = 6lb/5 - lb
= 1 lb /5
% change = 1lb/5 / 6lb/5 × 100%
= 50/3 %
= 16.67%
let breadth be b.
area = lb
Increased length = l + l ×50/100
= 3l/2
Decreased breadth = b - b ×20/100
= 4b/5
New Area = 3l/2 × 4n/5 = 6lb/5
Change in area = 6lb/5 - lb
= 1 lb /5
% change = 1lb/5 / 6lb/5 × 100%
= 50/3 %
= 16.67%
Sunnygandhari:
Incorrct
Is 20% the right answer.
??
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