Question

a diagonal of a parallogram divides into 2 congrent triangles proff​

Answer 1

In these two triangles, one side and two angles made on this side are equal. Therefore by ASA rule of congruence: △ABC ≅ △ADC. ... Therefore, it is proved that the diagonal of a parallelogram divides it into two congruent triangles and also opposite sides of a parallelogram are equal.

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Answer 2

Answer:

ANSWER 1

In these two triangles, one side and two angles made on this side are equal. Therefore by ASA rule of congruence: △ABC ≅ △ADC. ... Therefore, it is proved that the diagonal of a parallelogram divides it into two congruent triangles and also opposite sides of a parallelogram are equal.

ANSWER 2

consider Δ ABC and Δ ACD

Since the line segments AB+CD are parallel

to each other and AC is a transversal

∠ ACB = ∠ CAD.

AC = AC (common side)

∠CAB = ∠ ACD.

Thus, by ASA criteria

ΔABC ≅ ΔACD

The corresponding part of the congruent

triangle are congruent

AB = CD + AD = BC

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THE PHOTO IS OF 2 ANSWER

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