Question

A diagonal of a quadrilateral is 39 cm and the perpendiculars drawn to it from the opposite vertices are 14.7 cm and 15.3 cm. Its area is sq. cm.​

Answer 1

13453m is the answer
And mark it as brainliest answer

Answer 2

The area of the quadrilateral is 585 sq. cm.

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Let's understand a few concepts:

To solve the given problem we will use the following formula:

$\boxed{\bold{Area\:of\:quadrilateral = \frac{1}{2} \times [diagonal \:length]\times [sum\:of\:2\:perpendicular\:heights]}}$

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Let's solve the given problem:

The length of the diagonal of the quadrilateral (d) = 39 cm

The length of the two perpendicular heights drawn from the opposite vertices,

(h₁) = 14.7 cm and (h₂) = 15.3 cm

Therefore, by using the above formula, we get

The area of the given quadrilateral is,

= $\frac{1}{2} \times d \times (h_1+ h_2)$

= $\frac{1}{2} \times 39 \times (14.7+ 15.3)$

= $\frac{1}{2} \times 39 \times30$

= $39 \times 15$

= $\bold{585\:sq.\:cm}$

Thus, its area is 585 sq. cm.

#SPJ3

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