Question

A diagonal of a quadrilateral is 40 m long and the
perpendiculars to it from the opposite corners
are 8 m and 10 m respectively. Find its area. ​

Answer 1

Answer:

$360 {m}^{2}$

Step-by-step explanation:

Area of quadrilateral =

$\frac{1}{2} \times 40 \times 8 + \frac{1}{2} \times 40 \times 10$

$20 \times 8 + 20 \times 10$

$160 + 200$

$360 {m}^{2}$

Answer 2

Let the diagonal = d= 4o m

perpendiculars to the diagonal are h1, h2

h1 = 8m

h2 =10m

area of the quadrilateral = (h1+h2)d/2

= (8+10)*40/2

=18*20

=360sq m