a diagonal of a quadrilateral is 40m long and the perpendiculars to it form the opposite corners are 8m and 10 m respectively . find its area (fog.11.15)
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Answer:
Area of 1st triangle = 1/2 * base * height
=1/2* 40*10
=200 sq. M.
Area of 2nd triangle = 1/2* base * height
= 1/2*40*8
=160 sq. M.
Total area = 200+160
=360sq.m
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