A diagonal of a quadrilateral is 80 cm in length and the lengths of perpendiculars to it from the opposite vertices are 5.8 cm and 7.6 cm. Find the area of the quadrilateral.
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Step-by-step explanation:
Let ABCD be the figure
We have, AD= 80cm
dividing it into two triangles,
Thus the opposite perpendicular vertices qualifies height of those triangle.
In ∆ ABD
area= 1/2(b×h)
= 1/2(80cm×7.6cm)
= 40cm×7.6cm
=304cm²
In ∆ ACD
area= 1/2 (b×h
= 1/2(80cm×5.8cm)
= 40cm×5.8cm
= 232cm²
Now area of ABCD = 304cm²+232cm²= 536cm²
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