Question

a diagonal of a rectangle is inclined to one side of the rectangle at 25° what is the measure of acute angle​

Answer 1

Step-by-step explanation:

In △BOC,

∠OBC=∠OCB ----- (Opposite angle of isosceles triangle)

∠OBC+∠OCB+∠BOC=180

∘

25

∘

+25

∘

+∠BOC=180

∘

Therefore, ∠BOC=130

∘

So, ∠AOB+∠BOC=180

∘

--------(Linear pair)

∠AOB=180

∘

−130

∘

∠AOB=50

∘

So, the acute angle between the diagonal is 50

∘

.

solution

Answer 2

Step-by-step explanation:

In △BOC,

∠OBC=∠OCB ----- (Opposite angle of isosceles triangle)

∠OBC+∠OCB+∠BOC=180∘

25∘+25∘ +∠BOC=180∘

Therefore, ∠BOC=130∘

So, ∠AOB+∠BOC=180∘--------(Linear pair)

∠AOB=180∘ −130∘

∠AOB=50∘

So, the acute angle between the diagonal is 50°

Hope this is helpful