Question

A diagram shows a uniform bar supported at the middle point o.a weight of 40gf is placed at a distance 40 cm to the left of the point o.how can u balance the bar with a weight of 80gf​

Answer 1

We use the rule related to the moments of force :    or torque:
   which is  force (or weight)  multiplied by  the arm length from the pivot,  in this case , that is  the middle point  "O".

Place 80gf to the right of  O on the bar at a distance "X".  Then
          80gf * X = 40 gf * 40 cm
 
so  X = 20 cm.   place the 80gf at 20 cm to the right of o.

Answer 2

Answer:

hope it helps u well

Explanation:

plzz mark mee as brain list plzz